Optimal. Leaf size=190 \[ \frac{4 \sin (a+b x) \sin ^{\frac{7}{2}}(2 a+2 b x)}{5 b}+\frac{7 \sin (a+b x) \sin ^{\frac{3}{2}}(2 a+2 b x)}{6 b}-\frac{14 \sin ^{\frac{5}{2}}(2 a+2 b x) \cos (a+b x)}{15 b}-\frac{7 \sin ^{-1}(\cos (a+b x)-\sin (a+b x))}{8 b}-\frac{7 \sqrt{\sin (2 a+2 b x)} \cos (a+b x)}{4 b}+\frac{\sin ^{\frac{11}{2}}(2 a+2 b x) \csc ^3(a+b x)}{5 b}+\frac{7 \log \left (\sin (a+b x)+\sqrt{\sin (2 a+2 b x)}+\cos (a+b x)\right )}{8 b} \]
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Rubi [A] time = 0.186188, antiderivative size = 190, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 5, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.227, Rules used = {4300, 4308, 4301, 4302, 4305} \[ \frac{4 \sin (a+b x) \sin ^{\frac{7}{2}}(2 a+2 b x)}{5 b}+\frac{7 \sin (a+b x) \sin ^{\frac{3}{2}}(2 a+2 b x)}{6 b}-\frac{14 \sin ^{\frac{5}{2}}(2 a+2 b x) \cos (a+b x)}{15 b}-\frac{7 \sin ^{-1}(\cos (a+b x)-\sin (a+b x))}{8 b}-\frac{7 \sqrt{\sin (2 a+2 b x)} \cos (a+b x)}{4 b}+\frac{\sin ^{\frac{11}{2}}(2 a+2 b x) \csc ^3(a+b x)}{5 b}+\frac{7 \log \left (\sin (a+b x)+\sqrt{\sin (2 a+2 b x)}+\cos (a+b x)\right )}{8 b} \]
Antiderivative was successfully verified.
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Rule 4300
Rule 4308
Rule 4301
Rule 4302
Rule 4305
Rubi steps
\begin{align*} \int \csc ^3(a+b x) \sin ^{\frac{9}{2}}(2 a+2 b x) \, dx &=\frac{\csc ^3(a+b x) \sin ^{\frac{11}{2}}(2 a+2 b x)}{5 b}+\frac{16}{5} \int \csc (a+b x) \sin ^{\frac{9}{2}}(2 a+2 b x) \, dx\\ &=\frac{\csc ^3(a+b x) \sin ^{\frac{11}{2}}(2 a+2 b x)}{5 b}+\frac{32}{5} \int \cos (a+b x) \sin ^{\frac{7}{2}}(2 a+2 b x) \, dx\\ &=\frac{4 \sin (a+b x) \sin ^{\frac{7}{2}}(2 a+2 b x)}{5 b}+\frac{\csc ^3(a+b x) \sin ^{\frac{11}{2}}(2 a+2 b x)}{5 b}+\frac{28}{5} \int \sin (a+b x) \sin ^{\frac{5}{2}}(2 a+2 b x) \, dx\\ &=-\frac{14 \cos (a+b x) \sin ^{\frac{5}{2}}(2 a+2 b x)}{15 b}+\frac{4 \sin (a+b x) \sin ^{\frac{7}{2}}(2 a+2 b x)}{5 b}+\frac{\csc ^3(a+b x) \sin ^{\frac{11}{2}}(2 a+2 b x)}{5 b}+\frac{14}{3} \int \cos (a+b x) \sin ^{\frac{3}{2}}(2 a+2 b x) \, dx\\ &=\frac{7 \sin (a+b x) \sin ^{\frac{3}{2}}(2 a+2 b x)}{6 b}-\frac{14 \cos (a+b x) \sin ^{\frac{5}{2}}(2 a+2 b x)}{15 b}+\frac{4 \sin (a+b x) \sin ^{\frac{7}{2}}(2 a+2 b x)}{5 b}+\frac{\csc ^3(a+b x) \sin ^{\frac{11}{2}}(2 a+2 b x)}{5 b}+\frac{7}{2} \int \sin (a+b x) \sqrt{\sin (2 a+2 b x)} \, dx\\ &=-\frac{7 \cos (a+b x) \sqrt{\sin (2 a+2 b x)}}{4 b}+\frac{7 \sin (a+b x) \sin ^{\frac{3}{2}}(2 a+2 b x)}{6 b}-\frac{14 \cos (a+b x) \sin ^{\frac{5}{2}}(2 a+2 b x)}{15 b}+\frac{4 \sin (a+b x) \sin ^{\frac{7}{2}}(2 a+2 b x)}{5 b}+\frac{\csc ^3(a+b x) \sin ^{\frac{11}{2}}(2 a+2 b x)}{5 b}+\frac{7}{4} \int \frac{\cos (a+b x)}{\sqrt{\sin (2 a+2 b x)}} \, dx\\ &=-\frac{7 \sin ^{-1}(\cos (a+b x)-\sin (a+b x))}{8 b}+\frac{7 \log \left (\cos (a+b x)+\sin (a+b x)+\sqrt{\sin (2 a+2 b x)}\right )}{8 b}-\frac{7 \cos (a+b x) \sqrt{\sin (2 a+2 b x)}}{4 b}+\frac{7 \sin (a+b x) \sin ^{\frac{3}{2}}(2 a+2 b x)}{6 b}-\frac{14 \cos (a+b x) \sin ^{\frac{5}{2}}(2 a+2 b x)}{15 b}+\frac{4 \sin (a+b x) \sin ^{\frac{7}{2}}(2 a+2 b x)}{5 b}+\frac{\csc ^3(a+b x) \sin ^{\frac{11}{2}}(2 a+2 b x)}{5 b}\\ \end{align*}
Mathematica [A] time = 0.434573, size = 100, normalized size = 0.53 \[ \frac{7 \left (\log \left (\sin (a+b x)+\sqrt{\sin (2 (a+b x))}+\cos (a+b x)\right )-\sin ^{-1}(\cos (a+b x)-\sin (a+b x))\right )-\frac{2}{3} \sqrt{\sin (2 (a+b x))} (10 \cos (a+b x)+9 \cos (3 (a+b x))+2 \cos (5 (a+b x)))}{8 b} \]
Antiderivative was successfully verified.
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Maple [C] time = 26.75, size = 441, normalized size = 2.3 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \csc \left (b x + a\right )^{3} \sin \left (2 \, b x + 2 \, a\right )^{\frac{9}{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.573756, size = 802, normalized size = 4.22 \begin{align*} -\frac{8 \, \sqrt{2}{\left (32 \, \cos \left (b x + a\right )^{5} - 4 \, \cos \left (b x + a\right )^{3} - 7 \, \cos \left (b x + a\right )\right )} \sqrt{\cos \left (b x + a\right ) \sin \left (b x + a\right )} - 42 \, \arctan \left (-\frac{\sqrt{2} \sqrt{\cos \left (b x + a\right ) \sin \left (b x + a\right )}{\left (\cos \left (b x + a\right ) - \sin \left (b x + a\right )\right )} + \cos \left (b x + a\right ) \sin \left (b x + a\right )}{\cos \left (b x + a\right )^{2} + 2 \, \cos \left (b x + a\right ) \sin \left (b x + a\right ) - 1}\right ) + 42 \, \arctan \left (-\frac{2 \, \sqrt{2} \sqrt{\cos \left (b x + a\right ) \sin \left (b x + a\right )} - \cos \left (b x + a\right ) - \sin \left (b x + a\right )}{\cos \left (b x + a\right ) - \sin \left (b x + a\right )}\right ) + 21 \, \log \left (-32 \, \cos \left (b x + a\right )^{4} + 4 \, \sqrt{2}{\left (4 \, \cos \left (b x + a\right )^{3} -{\left (4 \, \cos \left (b x + a\right )^{2} + 1\right )} \sin \left (b x + a\right ) - 5 \, \cos \left (b x + a\right )\right )} \sqrt{\cos \left (b x + a\right ) \sin \left (b x + a\right )} + 32 \, \cos \left (b x + a\right )^{2} + 16 \, \cos \left (b x + a\right ) \sin \left (b x + a\right ) + 1\right )}{96 \, b} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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